考研高数公式😑
每天起床第一句,每天起床第一句 泰勒公式记一记 -。-
泰勒公式
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$e^x = 1+x+\frac{x^2}{2!}+...+\frac{x^n}{n!}$
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$sinx = x-\frac{x^3}{3!}+...+(-1)^n\frac{x^{2n+1}}{(2n+1)!}$
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$cosx = 1-\frac{x^2}{2!}+...+(-1)^n\frac{x^{2n}}{(2n)!}$
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$ln(1+x) = x-\frac{x^2}{2}+...+(-1)^{n-1}\frac{x^n}{n}$ ,
$-1< x\leqslant 1$
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$\frac{1}{1-x} = 1+x+x^2+...+x^n$ ,
|x|<1
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$\frac{1}{1+x} = 1-x+x^2-...+(-1)^nx^n$
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$(1+x)^a = 1+ax+\frac{a(a-1)}{2}x^2+O(x^2)$
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$tanx = x+\frac{1}{3}x^3+O(x^3)$
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$arcsinx = x+\frac{1}{6}x^3+O(x^3)$
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$arctanx = x-\frac{1}{3}x^3+O(x^3)$
高阶导数
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$a^{x^{(n)}} = a^x(lna)^n$ ,
$a>0, a\neq 1$
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$e^{x^{(n)}} = e^x$
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$(sinkx)^{(n)} = k^nsin(kx+n\cdot \frac{\pi}{2})$
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$(coskx)^{(n)} = k^ncos(kx+n\cdot \frac{\pi}{2})$
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$(lnx)^{(n)} = (-1)^{n-1} \cdot \frac{(n-1)!}{x^n}$
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$(\frac{1}{x})^{(n)} = (-1)^n \cdot \frac{n!}{x^{n+1}}$
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$[ln(1+x)]^{(n)} = (-1)^{n-1} \cdot \frac{(n-1)!}{(1+x)^n}$
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$(\frac{1}{1+a})^{(n)} = (-1)^n \cdot \frac{n!}{(x+a)^{n+1}}$
- * $[(x+x_0)^m]^{(n)} = m(m-1) \cdot \cdot \cdot (m-n+1)(x+x_0)^{m-n}$
源码区(LaTeX)
// 泰勒公式
e^x = 1+x+\frac{x^2}{2!}+...+\frac{x^n}{n!}
sinx = x-\frac{x^3}{3!}+...+(-1)^n\frac{x^{2n+1}}{(2n+1)!}
cosx = 1-\frac{x^2}{2!}+...+(-1)^n\frac{x^{2n}}{(2n)!}
ln(1+x) = x-\frac{x^2}{2}+...+(-1)^{n-1}\frac{x^n}{n}
\frac{1}{1-x} = 1+x+x^2+...+x^n$ ,|x|<1
\frac{1}{1+x} = 1-x+x^2-...+(-1)^nx^n
(1+x)^a = 1+ax+\frac{a(a-1)}{2}x^2+O(x^2)
tanx = x+\frac{1}{3}x^3+O(x^3)
arcsinx = x+\frac{1}{6}x^3+O(x^3)
arctanx = x-\frac{1}{3}x^3+O(x^3)
// 高阶导数
a^{x^{(n)}} = a^x(lna)^n ,a>0, a\neq 1
e^{x^{(n)}} = e^x
(sinkx)^{(n)} = k^nsin(kx+n\cdot \frac{\pi}{2})
(coskx)^{(n)} = k^ncos(kx+n\cdot \frac{\pi}{2})
(lnx)^{(n)} = (-1)^{n-1} \cdot \frac{(n-1)!}{x^n}
(\frac{1}{x})^{(n)} = (-1)^n \cdot \frac{n!}{x^{n+1}}
[ln(1+x)]^{(n)} = (-1)^{n-1} \cdot \frac{(n-1)!}{(1+x)^n}
(\frac{1}{1+a})^{(n)} = (-1)^n \cdot \frac{n!}{(x+a)^{n+1}}
[(x+x_0)^m]^{(n)} = m(m-1) \cdot \cdot \cdot (m-n+1)(x+x_0)^{m-n}